On Mon, 9 May 2005 11:06:47 -0400, Lee Bell <[log in to unmask]> wrote: >> Official solution: >> Scenario 1: Move each tenant to the next higher room number. In this >> case >> room 1 becomes free for La Poisson. >> Scenario 2: Move each tenant to the room with double their room number >> (e.g. tenant of room n goes to room 2n). In this case, the odd numbered >> rooms are free so Herr Banach can assign waiting customer k to room 2k-1 >> (e.g. the first in line goes to room 1, the second to room 3, the third to >> room 5, etc.) > >Leave it to a bunch of mathematicians to complicate things. Both solutions >force everybody to move. A much easier solution, at least for the guests, >is simply to renumber the rooms. Since Ostrich Lee proudly placed me on his "blocked sender's list", he obviously did not (1) see MY stated solutions, which mentioned "renumber": RF> La Poisson simply asks for the manager of the Hilbert hotel, RF> Mr. Banach to re-assign the room numbers by adding 1 more room RF> to it. RF> If you're a physicist, you would ask for manager Banach to add RF> countably infinitely many rooms to the Hilber hotel in ONE RF> re-assignment of room numbers, for the infinitely many NEDs. (2) Since Mr. Ostrich Lee is NEITHER a physicist (from his buoyancy thread blunders) nor a mathematician (for not knowing even what a linear function is), he obviously is unaware that the ideas of re-assignment and re-allocation of hotel rooms are "isomorphic", "homeomorphic", or otherwise mathematically "equivalent", and they "SIMPLIFY" and "UNIFY" concepts rather than "complicate things". -- Bob.