Wirt Atmar ([log in to unmask]) wrote: : Similarly, what's the probability that a one in three chance occurs if you : (or God) take three shots at it. : 1 3 3 1 : Again, the probability becomes 1 - (1/3)^3, or 8/9ths. Are you sure you want 1 3 3 1? This is for (1/2)^3, or 7/8ths, 3 chances of 1 in 2. (And the expression you had is 26/27ths.) Of course of you take 1 3 3 1 and insert a=2 and b=1 (and divide by 3^3) you get: 8 12 6 1, again with the 1 - 1/27 * To join/leave the list, search archives, change list settings, * * etc., please visit http://raven.utc.edu/archives/hp3000-l.html *