Cathlene's suggestion would work. It really isn't that hard to calculate day
of year (search Raven for past discussions of why what Raghu asks for is *
not * a Julian date, and that this confusion is IBM's fault). It's so
straightforward that the OS gives it to us for free as HPDOY. While you are
getting system variables, get HPYEAR, HPYYYY, HPYYYYMMDD or HPDATETIME, and
manipulate as needed to get the YY part.

Stefan points to functions, which do work with the actual Julian Date. But
this is not what Raghu is asking for.

Greg Stigers

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