On Mon, 9 May 2005 11:06:47 -0400, Lee Bell <[log in to unmask]> wrote:

>> Official solution:
>> Scenario 1:  Move each tenant to the next higher room number.  In this
>> case
>> room 1 becomes free for La Poisson.
>> Scenario 2:  Move each tenant to the room with double their room number
>> (e.g. tenant of room n goes to room 2n).  In this case, the odd numbered
>> rooms are free so Herr Banach can assign waiting customer k to room 2k-1
>> (e.g. the first in line goes to room 1, the second to room 3, the third
to
>> room 5, etc.)
>
>Leave it to a bunch of mathematicians to complicate things.  Both
solutions
>force everybody to move.  A much easier solution, at least for the guests,
>is simply to renumber the rooms.


Since Ostrich Lee proudly placed me on his "blocked sender's list",  he
obviously did not

(1) see MY stated solutions, which mentioned "renumber":

RF>  La Poisson simply asks for the manager of the Hilbert hotel,
RF>  Mr. Banach to re-assign the room numbers by adding 1 more room
RF>  to it.

RF> If you're a physicist, you would ask for manager Banach to add
RF> countably infinitely many rooms to the Hilber hotel in ONE
RF> re-assignment of room numbers, for the infinitely many NEDs.


(2)  Since Mr. Ostrich Lee is NEITHER a physicist (from his buoyancy
     thread blunders) nor a mathematician (for not knowing even what
     a linear function is), he obviously is unaware that

the ideas of re-assignment and re-allocation of hotel rooms are
"isomorphic", "homeomorphic", or otherwise mathematically
"equivalent", and they "SIMPLIFY" and "UNIFY" concepts rather
than "complicate things".

-- Bob.