I have been using CALENDAR and ALMANAC intrinsics in Cobol programs
for the longest time now and they work correctly. They return the
correct dates. So I'm not sure what your problem is.
I wrote a quickie program to satisfy my own curiosity and it is
indeed satisfied!
So here's the source for you to compile and try yourself:
IDENTIFICATION DIVISION.
PROGRAM-ID. TEST.
ENVIRONMENT DIVISION.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 WS-DATE-ERROR-TABLE COMP.
05 WS-DATE-ERROR PIC 9(04) COMP OCCURS 2.
01 WS-DAY-NUM PIC S9(04) COMP VALUE ZEROES.
01 WS-WEEKDAY-NUM PIC S9(04) COMP VALUE ZEROES.
01 WS-YEAR-NUM PIC S9(04) COMP VALUE ZEROES.
01 WS-MONTH-NUM PIC S9(04) COMP VALUE ZEROES.
01 WS-START-DATE PIC 9(04) COMP VALUE ZEROES.
PROCEDURE DIVISION.
A000-MAINLINE.
CALL INTRINSIC "CALENDAR" GIVING WS-START-DATE.
INITIALIZE WS-DATE-ERROR-TABLE,
WS-YEAR-NUM,
WS-MONTH-NUM,
WS-DAY-NUM,
WS-WEEKDAY-NUM.
CALL INTRINSIC "ALMANAC" USING WS-START-DATE,
WS-DATE-ERROR-TABLE,
WS-YEAR-NUM,
WS-MONTH-NUM,
WS-DAY-NUM,
WS-WEEKDAY-NUM
END-CALL.
IF WS-DATE-ERROR(1) NOT = ZEROES THEN
DISPLAY 'DATE CONVERSION ERROR'
STOP RUN
END-IF.
DISPLAY 'YEAR IS=>' WS-YEAR-NUM "<".
DISPLAY 'MONTH IS=>' WS-MONTH-NUM "<".
DISPLAY 'DAY IS=>' WS-DAY-NUM "<".
DISPLAY 'WEEKDAY IS=>' WS-WEEKDAY-NUM "<".
STOP RUN.
Here's the run time results:
:RUN TEST.NMPRG
YEAR IS=>+0104<
MONTH IS=>+0010<
DAY IS=>+0018<
WEEKDAY IS=>+0002<
Add 1900 to the year and you get 2004. Fine.
The month is 10 (October). Fine.
The day is 18, which is today, October 18th. Fine.
The weekday is 2, so count Sunday as day one and so today Monday
is day 2.
This works fine.....
So what's the problem........??
Brian Donaldson.
On Mon, 18 Oct 2004 12:03:58 -0500, Peter Smithson
<[log in to unmask]> wrote:
> Hi,
>
>I must be doing something really stupid.
>
>
>The documentation for item 6 (file creation date) is that it uses the
>CALENDAR intrinsic format which says -
>
>Bits Value/Meaning
>7:9 Day of year
>0:7 Year since 1900
>
>I get a bit confused with this notation. Is that saying that the low 9
>bits are the year and the high 7 is the year?
>
>So today is year 104, day 292. So the value I'd expect is
>
>292 + 104 * (2^9) which is 53540.
>
>Or if the year is 04 then it'd be 2340.
>
>When I run a test program on MPE I get 1996 which is day 460 year 03.
>
>I've tried out a few other combinations but I can't get it right. What
>have I done wrong? I get the same result from calling CALENDAR.
>
>Thanks.
>
>Peter
>--
>http://www.beluga.freeserve.co.uk
>
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