Brice writes:

> I need a proof of this
>
>  "e^(i*pi) = -1"  -- Euler

Two different methods of proving Euler's Equation to be true appear at:

     http://perch.cimr.cam.ac.uk/Course/Adv_diff1/Euler.html

Euler's Equation states that:

     e^(i * alpha) = cos(alpha) + i * sin(alpha)

If you let alpha = pi, then the righthand side becomes:

     e^(i * pi) = -1 + i * 0

Wirt Atmar

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