this is my final answer. it was forwarded to me by my better half. i have to
concur with my wife that this is the right formula which gives an answer of
0.015625 or 1/64.

thanks, it was fun

dennis profeta
----- Original Message -----
From: Profeta, Dennis <[log in to unmask]>
To: <[log in to unmask]>
Sent: Wednesday, March 01, 2000 11:17 AM
Subject: FW: prob


>
>
> > -----Original Message-----
> > From: nery o.profeta [SMTP:[log in to unmask]]
> > Sent: Wednesday, March 01, 2000 11:13 AM
> > To: [log in to unmask]
> > Subject: prob
> >
> > P(A & B) = P(A) x P(B, if A)
> > the probability that both events will happen is equal to probability
that
> > the
> > first will happen multiplied by the prob. that the second will happen
if
> > the
> > first already has.
> > e.g
> > the prob. of getting heads on one toss of a coin is .5 and so is the
prob
> > of
> > getting heads on a second toss. so the prob of getting 2 heads on both
> > tosses
> > is .5 x .5 = .25
> >
> > the chance of drawing one of the four aces in a deck of card is 4/52;
but
> > the
> > chance of drawing a second ace in the same deck of card is 3/51 . thus
4/52
> > x
> > 3/51 = .0045248.
> >
> > oks
> > nery
> >
> > ____________________________________________________________________
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>