Subject: | |
From: | |
Reply To: | |
Date: | Thu, 10 May 2001 22:36:00 -0700 |
Content-Type: | text/plain |
Parts/Attachments: |
|
|
> Ok, so let me see if I get this straight. What Steve is
> saying is that if
> I stick an 820 ohm, with no more then a 5% variance, 1/2 watt
> resister on
> the positive side of my 17.5VDC power source that it well
> come out the other end of the resister as 2VDC or less?
Doesn't matter which lead you use for the resistor (just make sure it's in
series, not parallel, with the LED!). And 820 Ohms is just the minimum for
this application; anything from there up to probably 1.2KOhm will work fine
(plus, if you use 1KOhm or higher, you can use a 1/4 Watt instead of 1/2
Watt resistor). Going much above 2KOhm will make the LED pretty dim.
* To join/leave the list, search archives, change list settings, *
* etc., please visit http://raven.utc.edu/archives/hp3000-l.html *
|
|
|