Hi Brad,
I dont have a Cobol version, but here is an SPLash version.
You should be able to translate it into Cobol easily enough
if you use the recently introduced Cobol routines for boolean
operations as described in the 6.0 communicator.
( HP_BYTE_XOR is the only one you need )
Regards,
Tad.
{
+----------------------------------------------------------------+
| CALCCRC16 : Calculate the CRC16 for a given byte string |
| data : byte array containing data to be crc'ed |
| nb : number of bytes in data. |
| crc : crc accumulator. |
+----------------------------------------------------------------+
}
Logical Procedure CALCCRC16(data,nb,crc);
value nb,crc;
integer nb;logical crc;
byte array data;
Begin
Integer i
;
Logical array CRC16TAB(0:255)=PB:=
$0000, $C0C1, $C181, $0140, $C301, $03C0, $0280, $C241,
$C601, $06C0, $0780, $C741, $0500, $C5C1, $C481, $0440,
$CC01, $0CC0, $0D80, $CD41, $0F00, $CFC1, $CE81, $0E40,
$0A00, $CAC1, $CB81, $0B40, $C901, $09C0, $0880, $C841,
$D801, $18C0, $1980, $D941, $1B00, $DBC1, $DA81, $1A40,
$1E00, $DEC1, $DF81, $1F40, $DD01, $1DC0, $1C80, $DC41,
$1400, $D4C1, $D581, $1540, $D701, $17C0, $1680, $D641,
$D201, $12C0, $1380, $D341, $1100, $D1C1, $D081, $1040,
$F001, $30C0, $3180, $F141, $3300, $F3C1, $F281, $3240,
$3600, $F6C1, $F781, $3740, $F501, $35C0, $3480, $F441,
$3C00, $FCC1, $FD81, $3D40, $FF01, $3FC0, $3E80, $FE41,
$FA01, $3AC0, $3B80, $FB41, $3900, $F9C1, $F881, $3840,
$2800, $E8C1, $E981, $2940, $EB01, $2BC0, $2A80, $EA41,
$EE01, $2EC0, $2F80, $EF41, $2D00, $EDC1, $EC81, $2C40,
$E401, $24C0, $2580, $E541, $2700, $E7C1, $E681, $2640,
$2200, $E2C1, $E381, $2340, $E101, $21C0, $2080, $E041,
$A001, $60C0, $6180, $A141, $6300, $A3C1, $A281, $6240,
$6600, $A6C1, $A781, $6740, $A501, $65C0, $6480, $A441,
$6C00, $ACC1, $AD81, $6D40, $AF01, $6FC0, $6E80, $AE41,
$AA01, $6AC0, $6B80, $AB41, $6900, $A9C1, $A881, $6840,
$7800, $B8C1, $B981, $7940, $BB01, $7BC0, $7A80, $BA41,
$BE01, $7EC0, $7F80, $BF41, $7D00, $BDC1, $BC81, $7C40,
$B401, $74C0, $7580, $B541, $7700, $B7C1, $B681, $7640,
$7200, $B2C1, $B381, $7340, $B101, $71C0, $7080, $B041,
$5000, $90C1, $9181, $5140, $9301, $53C0, $5280, $9241,
$9601, $56C0, $5780, $9741, $5500, $95C1, $9481, $5440,
$9C01, $5CC0, $5D80, $9D41, $5F00, $9FC1, $9E81, $5E40,
$5A00, $9AC1, $9B81, $5B40, $9901, $59C0, $5880, $9841,
$8801, $48C0, $4980, $8941, $4B00, $8BC1, $8A81, $4A40,
$4E00, $8EC1, $8F81, $4F40, $8D01, $4DC0, $4C80, $8C41,
$4400, $84C1, $8581, $4540, $8701, $47C0, $4680, $8641,
$8201, $42C0, $4380, $8341, $4100, $81C1, $8081, $4040;
For i:=0 until nb-1
do crc:=crc.(0:8) xor CRC16TAB(crc.(8:8) xor data(i));
CALCCRC16:=crc;
End;
Internet
From: [log in to unmask] on 14/10/99 22:24 GMT
Pour : HP3000-L
cc :
ccc: Tad BOCHAN
Objet : CRC Checksum with Cobol
Does anyone have a Cobol example of doing a CRC checksum on a data
record?
I'll be sending data over a socket between a C program on a 9000 and a
Cobol program on a 3000 so I'll have to do the same calculation with
both C and Cobol. If someone has already done this I would be interested
to know how it worked out.
In the HP3000-L archive, I saw some discussion about turning on the TCP
checksum but doesn't this incur substantial overhead?
--
Brad Feazell
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