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July 2002, Week 5

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From:
Tad Bochan <[log in to unmask]>
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Date:
Tue, 30 Jul 2002 17:52:38 +0200
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This is of course do-able in COBOL with the unstring verb but it
can be a bit tedious.

You could consider invoking a command file to do the parsing
by using call intrinsic "HPCICOMMAND"
(I dont think you have any migrations issues with this task ;-))
and then just retrieving the variables created by using
call intrinsic "HPCIGETVAR"
Here is what the command file could look like,

anyparm a_jobcard=:job jobname,mpeuser.acctname,group;otherparms
setvar jobcard anyparm(!a_jobcard)
setvar jobcard xword(jobcard)
setvar jfield1 rtrim(word (jobcard,";"))
setvar jfield2 rtrim(xword(jobcard,";"))
setvar jobid1  word(jfield1,,1)
setvar jobid2  word(jfield1,,2)
setvar jobid3  word(jfield1,,3)
if     pos(".",jobid1) > 0
       setvar jobid3 jobid2
       setvar jobid2 jobid1
       setvar jobid1 ""
endif
setvar myjobname  jobid1
setvar mympeuser  word(jobid2,".",1)
setvar myacctname word(jobid2,".",2)
setvar mylogongrp word(jobid3)
setvar myotherfld jfield2
deletevar jfield#,jobid#
return







Internet
[log in to unmask]@RAVEN.UTC.EDU - 30/07/2002 16:54


Veuillez répondre à [log in to unmask]

Envoyé par :      [log in to unmask]

Pour : HP3000-L

cc :


Objet :     Decomposing a !JOB card to single tokens - in COBOL


Greetings,

I'm writing a COBOL program that needs to break a !JOB card into it's
constituent parts.

For example;

field 1 = stream char and JOB
field 2 = job name (spaces if not supplied)
field 3 = user name
field 4 = user password (spaces if not supplied)
field 5 = account name
field 6 = account password (spaces if not supplied)
field 7 = group name (spaces if not supplied)
field 8 = group password (spaces if not supplied)
field 9 and onwards = any other jobcard parameters that are found

To prevent me from having to 'reinvent the wheel' is there anybody who has
done this and is willing to pass on a snippet (or more) of code?

regards,

Robert W.Mills
Systems Development Manager
Windsong Services

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