Hi Donna,
   um.... I believe the equation would be density*length minus overhead
amount....
                          so a 2400' tape at 6850 bpi would be:
                                 2400*12*6850 = 197,280,00 bytes max   (I
have no clue about the overhead calcs tho!)

                                 Note: this is of course based on me not
hitting any wrong keys on my HP 32S II calculator hehehe

                                So who will be the first to correct me :)
Since I doubt I have this right  hehe

Art "No guarentees in life :)" Bahrs

P.S. on a side note... we now have Longs Drug Stores up here in Oregon...
:) since they took over Drug Emporiums .... hmmm....




i guess this is an oldie but a goodie sorta question...
how much information can a 2400' reel (yes, reel) of tape
contain -- in theory.  i guess, perhaps, the better question
is -- does anyone remember the equation for calculating
this?       - d
--
Donna Garverick     Sr. System Programmer
925-210-6631        [log in to unmask]
>>>MY opinions, not Longs Drug Stores'<<<