HP3000-L Archives

January 2005, Week 3

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Subject:
From:
Tony Summers <[log in to unmask]>
Reply To:
Tony Summers <[log in to unmask]>
Date:
Fri, 21 Jan 2005 15:03:18 -0000
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I'd confer with that - for the outline of a proof (hey I haven't done
formal maths for 20 years, so don't belittle my outline).  

Start with a n digit number. 

xxxxxxYxxx 

Scramble that number 

xxYxxxxxxx

As far as "Y" is concerned the difference between the two numbers is 

00Y0000000 minus 
000000Y000 

Which will reduce to something like  

Y  * (100000 - 1000  )  

And even further to 

1000 * Y ( 100 - 1 ) = 1000 * y * "a guaranteed mutiple of 9".   

Repeat the above for all other digits in the original number - and sum
the results. 

And you can rely upon the fact that the sum of the digits of any
multiple of 9 is also a multiple of 9.  (I'm sure the proof for this
final statement can be found somewhere on the internet) 



-----Original Message-----
From: HP-3000 Systems Discussion [mailto:[log in to unmask]] On
Behalf Of Bob Comeau
Sent: 21 January 2005 13:03
To: [log in to unmask]
Subject: Re: [HP3000-L] Fun with numbers

It has to do with the fact that the difference between numbers which
have been transposed is always divisible by nine.  Jumbling up the
digits and finding the difference will give you such a number.

A number which is divisible by nine has digits which add up to a number
divisible by nine.

By removing one of those digits you can easily determine what it was by
determining what you need to make the total of the digits add up to
nine.

Not sure why he says to not circle a zero, you would think that would be
just as easy to determine, may be it's just a red herring.

Bob Comeau
Sr. Systems Programmer Analyst
Crossley Carpet Mills Ltd.
(902)895-5491 ex 139


-----Original Message-----
From: HP-3000 Systems Discussion [mailto:[log in to unmask]]On
Behalf Of John Dunlop
Sent: January 21, 2005 5:08 AM
To: [log in to unmask]
Subject: OT: Fun with numbers


To all you smart mathematicians out there,  can anyone explain to me (in
simple terms) how this works?

See :  http://digicc.com/fido/

I can't figure it out, especially as you can jumble up the numbers and
it still works.

Doh!

Cheers,

John Dunlop

E-mail : [log in to unmask]
Web : http://www.jdunlop.net

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