Since a J2 item is 4 bytes a J4 item would be 8 bytes and since the item
occurs 6 times the total length of the item would 6 x 8 = 48 bytes. An
easier way to determine this is by looking at the Offset column in the
Suprtool Form output that you showed. The offset of the Amounts item is 45
and the offset of the next item is 93 therefore the length of the Amounts
item is 93 - 45 = 48. Pretty easy, right?