HP3000-L Archives

January 1999, Week 2

HP3000-L@RAVEN.UTC.EDU

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Subject:
From:
Patrick Santucci <[log in to unmask]>
Reply To:
Patrick Santucci <[log in to unmask]>
Date:
Thu, 14 Jan 1999 15:03:43 -0600
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Donna Garverick wrote:

> a jamaica fully-populated with 9gb drives
> gives ~36gb of total storage.  to fill the enclosure with 4.3gb drives yields
> ~34gb -- a very small difference.

We have lots of the 4GB drives (which HP insists on labelling 4.3GB) in
Jamica boxes, and just got our first set of 9 GB drives. Guess what?
Their half-height, same size as the 4GB, so "fully populated" now means
you could put 8 of 'em in a Jamaica box and have a whopping 72GB of
disc...

Except, from what I can see, the 9GB drives (labelled 9.1 GB) are really
only 8.48 GB. This means a fully populated Jamaica box with 8 "9.1"GB
drives would yield 67.84 GB of disk space. At least, by my calculations:

At 256 bytes per sector, 4 sectors = 1024 bytes or 1k

35566208 sectors /    4 = 8891552.00 KB
   8891552.00 KB / 1024 =    8683.16 MB
      8683.16 MB / 1024 =       8.48 GB
therefore:
         8.48 GB x    8 =      67.84 GB

Using this same formula (16776624 sectors/4/1024/1024) the 4.3 GB disks
come out to 4.00 GB. So a Jamaica box fully populated with these babies
gives you 32.00 GB, not 34.

<second-guess mode>
Or am I doing something wrong?  2^10 = 1024 or 1KB, right?  And (2^10)^2
= 1048576 or 1 MB, which is the same as 1024^2, right? Please correct me
if I'm wrong on the math! (I won't take it personally; I'll blame Excel.
:-)
</second-guess mode>

Patrick
--
Patrick Santucci
Technical Services Systems Programmer
KVI, a division of Seabury & Smith, Inc.
Visit our site! http://www.kvi-ins.com
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
"If they try to rush me, I always say, 'I've only got
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