> -----Original Message-----
> Behalf Of Peter Smithson
> 
> The documentation for item 6 (file creation date) is that it uses the
> CALENDAR intrinsic format which says -
> 
> Bits   Value/Meaning
> 7:9   Day of year
> 0:7   Year since 1900
> 
> I get a bit confused with this notation.  Is that saying that 
> the low 9
> bits are the year and the high 7 is the year?

This is an "endian-ness" issue :)

looking at the value as a string-of-bits, they are numbered from 15 down to zero, i.e.:

           -------------------------------------------------
Bit pos:   |  |  |  |  |  |  |  |  |  |  |  |  |  |  |  |  |
           -------------------------------------------------
bit         1  1  1  1  1  1  0  0  0  0  0  0  0  0  0  0
number       5  4  3  2  1  0  9  8  7  6  5  4  3  2  1  0

> So today is year 104, day 292.  So the value I'd expect is
> 
> 292 + 104 * (2^9) which is 53540.

that seems to be correct:

988/COREDEV/TEMPTE%help calendar

  4. CALENDARTODATE, date function
  5. DATETOCALENDAR, date function
Which of the above would you like help on (or CR to exit)? 5
TODAY               [DATE]    Returns today's date.

CALENDARTODATE (I)  [DATE]    Returns the date represented by the
                              CALENDAR-intrinsic-format integer I.

DATETOCALENDAR (D)  [INT]     Returns the CALENDAR-intrinsic-format
                              representation of the date D.

988/COREDEV/TEMPTE%calc datetocalendar(today)
-11996, $FFFFD124, %37777750444, #65535/#53540, "...$"

> When I run a test program on MPE I get 1996 which is day 460 year 03.

since the "high-bit" is set, you get negative numbers (-11996); look to the right side of that output and you see that (sign extended), this is a positive 53540, exactly what you expected

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