Greg,

Try the following:
:setvar a SETVAR(b, 30+hpminute+(60*hphour))+SETVAR(newh,(b/60)mod
24)+SETVAR(newm,(b mod 60)

See example below:

:showvar hphour, hpminute
HPHOUR = 10
HPMINUTE = 54

:setvar a SETVAR(b, 30+hpminute+(60*hphour))+SETVAR(newh,(b/60)mod
24)+SETVAR(newm,(b mod 60))
:showvar new@
NEWH = 11
NEWM = 24

The above should also work across date changes..


Regards
Paul Christidis


HP-3000 Systems Discussion <[log in to unmask]> wrote on 02/19/2005
03:32:43 PM:

> > If HPMINUTE > 30 then you'd have to add some checking and math,
something
> > like
> > and IF ... THEN ... ELSE check to subtract 30 from the minutes and add
1
> > to the
> > hour.
> which is what I am trying to avoid having to do. I thought that maybe
there
> was some way to perhaps both add and subtract a value, and then take the
> absolute value of the result, or something cunning like that. I want to
> calculate once, not evaluate and then calculate, if you follow my
meaning.
> Again, best I've come up with is ((hour x 60) + 30) / 60 for the hour,
and
> mod ((hour x 60) + 30) 60 for the minutes.
>
> Greg Stigers
>
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