HP3000-L Archives

December 2006, Week 1

HP3000-L@RAVEN.UTC.EDU

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Subject:
From:
Nilesh Patel <[log in to unmask]>
Reply To:
Date:
Tue, 5 Dec 2006 09:58:55 +0100
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Not too difficult.

> can cle
> def d char*30=  parm prompt 'String:'
> def dd char*30 = pack(trunc(d))
> def d1  = index(dd,' ')
> def d2 = 1 if d1 < 30 and ' ' <> dd[d1+1:2] else 0
> def d3 char*30 =  dd if d2 = 0 else dd[1:d1]
> set rep spa 0 pag len 0
> set pag len 0 wid 256 rep lim 20000
> rep all
> go

String: SACRAMENTO CA

05 DEC 2006                                            MILAN ABS 
DICTIONARY                                              PAGE 
1

D                             DD                               D1     D2 
D3

 SACRAMENTO CA                SACRAMENTO CA                      11 
1SACRAMENTO

Records selected:  0
Lines printed:     3
Pages printed:     1

> go

String:SACRAMENTO

05 DEC 2006                                            MILAN ABS 
DICTIONARY                                              PAGE 
1

D                             DD                               D1     D2 
D3

SACRAMENTO                    SACRAMENTO                         11 
0SACRAMENTO

Records selected:  0
Lines printed:     3
Pages printed:     1

> 





Internet
[log in to unmask]@RAVEN.UTC.EDU - 05/12/2006 05:49
 
Please respond to [log in to unmask]
Sent by:        [log in to unmask]
To:     HP3000-L
cc: 
Subject:        [HP3000-L] quiz - how-to question


Is there a way, in Quiz, given String X, length 30, and String Y, length 
2, to
do the following?

1.  remove spaces from both left and right side of string X
2.  check to see if the last 2 characters of the result from #1 match 
String Y
3.  check to see if the 3rd to the last character of the result from #1 
equals
SPACE
4.  if #2 and #3 are true then assign String Z to the portion of the 
result from
#1, less 3 characters

In Visual Basic, the code would go something like this:

if right(trim(X),2)=Y and mid(trim(X),len(trim(X))-2,1)=" " then 
Z=left(trim
(X),len(trim(X))-3)

The business objective is to split a string which *might* have the state 
code
embedded into the city field such that we isolate the string value 
representing
the city (e.g., SACRAMENTO CA transforms to SACRAMENTO; or BUFFALO NY
transforms to BUFFALO).  So, from the above example, String X contains the
CITY and (maybe) the STATE code.  String Y = the STATE code.  We wish to
extract String Z (the CITY value).

I've dumped the data to MS ACCESS and achieved the desired results using
MS Access SQL, and am interested in performing the actions on the HP3000.

Any takers?  :-)

As always, thanks to the MPE gurus out there.
-Eben Yong
[log in to unmask]

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