I don't want to say that it doesn't work, but some of this code won't
compile with HP COBOL.
Also, I'd be leery of the check for leap year. I don't see where the
100-year rule is being implemented, and it looks to me like the 400-year
check is backwards.
Also, be careful about using an arithmetic expression with division and
multiplication, to check for divisibility. This might work with HP
COBOL, but some compilers use more significant digits for intermediate
results in an arithmetic expression, so an expression like (yyyy / 4 *
4) would always evaluate to true.
Walter
Walter J. Murray
-----Original Message-----
From: HP-3000 Systems Discussion [mailto:[log in to unmask]] On
Behalf Of Tracy Pierce
Sent: Wednesday, February 08, 2006 2:49 PM
To: [log in to unmask]
Subject: Re: [HP3000-L] HP COBOL routine to calculate the difference
between 2 dates
Eben, I already sent you my arduously bullet-proofed dtdif routine, but
it calcs exact days. for the calc you requested, try
01 jafemaapmajujuauseocnode value
'312831303130313130313031'.
05 days occurs 12.
01 date1.
05 d1ccyy pic 9999.
05 d1mm pic 99.
05 d1dd pic 99.
01 date2.
05 d2ccyy pic 9999.
05 d2mm pic 99.
05 d2dd pic 99.
01 diff.
05 dify pic 9999.
05 difm pic 99.
05 difd pic 99.
if date1 < date2
display 'please enter dates in ascending sequence'
else
if d1dd < d2dd
subtract 1 from d1mm
add days ( d1mm ) to d1dd
if ( d1mm > 2 or ( d1mm = 2 and d1dd > 28 ))
and ( d1ccyy / 4 * 4 = d1ccyy )
and not ( d1ccyy / 400 * 400 = d1ccyy )
* *d1 is a leap year; this is not pseudo code, it works.
add 1 to d1dd
end-if
end-if
compute difd = d1dd - d2dd
if d1mm < d2mm
subtract 1 from d1yy
add 12 to d1mm
endif
compute difm = d1mm - d2mm
compute dify = d1ccyy - d2ccyy
display 'difference is ' dify ' years, ' difm ' months, ' difd '
days.'
end-if
.
Tracy Pierce, GGBHTD
> -----Original Message-----
> From: Tracy Pierce
> Sent: Wednesday, February 08, 2006 2:21 PM
> To: 'Eben Yong'
> Subject: RE: HP COBOL routine to calculate the difference
> between 2 dates
>
> see prior. after reading the explanation, it occurs to me
> that it could be a lot simpler to state:
>
> 01 date1 pic s9(9) comp.
> 01 date2 pic s9(9) comp.
> 01 diff pic s9(9) comp.
>
> move 19530202 to date1
> move 20060208 to date2
> move zero to diff
> call dtdif using date1 date2 diff
> *diff holds my age in days.
>
> or
>
> move 19530202 to date1
> move 0 to date2
> move 365 to diff
> *date2 holds the date 365 days after date1.
>
> > -----Original Message-----
> > From: HP-3000 Systems Discussion
> > [mailto:[log in to unmask]] On Behalf Of Eben Yong
> > Sent: Wednesday, February 08, 2006 1:44 PM
> > To: [log in to unmask]
> > Subject: HP COBOL routine to calculate the difference
> between 2 dates
> >
> > I'm slightly embarrassed to even post this question, as I
> > feel I should be
> > able to produce this code in a snap, but for some reason my
> > brain must be
> > somewhat tired today. In any event, excuses aside, here is
> > the question:
> >
> > Would someone pls share their COBOL code that will calculate the
> > difference between two given dates, and return the results in
> > terms of
> > years, months, and days?
> >
> > For example, the difference between 20060125 and 20040611
> is 1 year 7
> > months and 14 days.
> >
> > Care to share?
> > Thanks as always,
> > Eben Yong
> > Health Plan of San Mateo
> >
> > * To join/leave the list, search archives, change list settings, *
> > * etc., please visit http://raven.utc.edu/archives/hp3000-l.html *
> >
>
* To join/leave the list, search archives, change list settings, *
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